How to pad a string with leading zeros in Python 3 [duplicate]

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One of the following string values or a user supplied function,,Pads with the edge values of array

Example_snippet/controller/utility/_python.js/ padding_func(vector, iaxis_pad. . .
padding_func(vector, iaxis_pad_width, iaxis, kwargs)
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The format string is composed of zero or more directives: ordinary characters (excluding %) that are copied directly to the result and conversion specifications, each of which results in fetching its own parameter, , The c type specifier ignores padding and width , Attempting to use a combination of the string and width specifiers with character sets that require more than one byte per character may result in unexpected results , Returns a string produced according to the formatting string format

Example_snippet/controller/utility/_python.js/ There are 5 monkeys in the tre. . .
There are 5 monkeys in the tree
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Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers , About ,Make use of the zfill() helper method to left-pad any string, integer or float with zeros; it's valid for both Python 2,x and Python 3

Example_snippet/controller/utility/_python.js/ print(str(1).zfill(3)) # Expec. . .
# Expected output: 001
Step 2 continued with str(string).zfill(width) # Whe. . .
# Where string represents a string, an integer or a float, and
# width, the desired length to left - pad.
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Converting an integer to an n-bit binary number results in its binary representation containing leading zeros up to length n, For example, to convert the integer 5 to a 6-bit binary results in 000101

Example_snippet/controller/utility/_python.js/ x = 12 print(format(x, '08b')). . .
x = 12
print(format(x, '08b'))
print(format(x, '010b'))
Step 2 continued with 00001100 0000001100 . . .
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Example_snippet/controller/utility/_python.js/ str(1).zfill(2) # 1 will be '0. . .
# 1 will be '01'

# 23 will be '0023'
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The zfill() method adds zeros (0) at the beginning of the string, until it reaches the specified length,,If the value of the len parameter is less than the length of the string, no filling is done

Example_snippet/controller/utility/_leading.js/ zfill(). . .

In all methods, we assume that the integer has less than 5 characters, ,Method 1: Format String,Example: For integer 42, you want to fill it up with leading zeros to the following string with 5 characters: '00042'

Example_snippet/controller/utility/_leading.js/ # Integer value to be converte. . .
# Integer value to be converted
i = 42

# Method 1: Format String
s1 = f '{i:05d}'
# 00042
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