How to let regex ignore everything between brackets?

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6 Answers

regexignore
90%

My mistake - I forgot the requirement that everything that is not between brackets, should be returned lowercase. So, again, what is between brackets is left alone. Is it possible with this regex to return the rest in lowercase? – Pr0no Feb 10 '12 at 0:23 ,Means match anything that is not included in the negated character class, but only if there is no closing bracket ahead without a opening before, this is done by the negative lookahead (?![^{]*}).,But I need the regex to always ignore whatever is in between { and }. So the desired output would be:, Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers

Try this

[ ^ a - zA - Z {}] + ( ? ![ ^ {
   ] *
})

Means match anything that is not included in the negated character class, but only if there is no closing bracket ahead without a opening before, this is done by the negative lookahead (?![^{]*}).

$string preg_replace('/[^a-zA-Z {}]+(?![^{]*})/', '', $string);
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88%

Consider the following string:,But I need the regex to always ignore whatever is in between { and }. So the desired output would be:,How can I let the regex ignore what is between { and }?,Means match anything that is not included in the negated character class, but only if there is no closing bracket ahead without a opening before, this is done by the negative lookahead (?![^{]*}).

Consider the following string:

I have been driving to {
   Palm.!.Beach: 100
}
and it.was.great!!

I use the following regex to delete all punctuation:

$string preg_replace('/[^a-zA-Z ]+/', '', $string);

This outputs:

I have been driving to PalmBeach and it was great!!

But I need the regex to always ignore whatever is in between { and }. So the desired output would be:

I have been driving to {
   Palm.!.Beach: 100
}
and it was great
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72%

Means match anything that is not included in the negated character class, but only if there is no closing bracket ahead without a opening before, this is done by the negative lookahead (?![^{]*}).,The ++ and *+ will consume as much as they can and give nothing back for backtracking. This technique is described in perlre(1) as the most efficient way to do this kind of matching.,The standard disclaimer applies: Parsing HTML with regular expressions is not ideal. Success depends on the well-formedness of the input on a character-by-character level. If you cannot guarantee this, the regex will fail to do the Right Thing at some point.,Something like this problem of matching nested brackets is not possible to solve using a single regex. Here is my take to resolve your problem:

Consider the following string:

I have been driving to {
   Palm.!.Beach: 100
}
and it.was.great!!

I use the following regex to delete all punctuation:

$string preg_replace('/[^a-zA-Z ]+/', '', $string);

This outputs:

I have been driving to PalmBeach and it was great!!

But I need the regex to always ignore whatever is in between { and }. So the desired output would be:

I have been driving to {
   Palm.!.Beach: 100
}
and it was great
load more v
65%

I use the following regex to delete all punctuation:,But I need the regex to always ignore whatever is in between { and }. So the desired output would be:,Means match anything that is not included in the negated character class, but only if there is no closing bracket ahead without a opening before, this is done by the negative lookahead (?![^{]*}).,Consider the following string:

Consider the following string:

I have been driving to {
   Palm.!.Beach: 100
}
and it.was.great!!

I use the following regex to delete all punctuation:

$string preg_replace('/[^a-zA-Z ]+/', '', $string);

This outputs:

I have been driving to PalmBeach and it was great!!

But I need the regex to always ignore whatever is in between { and }. So the desired output would be:

I have been driving to {
   Palm.!.Beach: 100
}
and it was great
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75%

$text = 'ignore everything except this {{ text1  }}';
preg_match('#\{\{(.*?)\}\}#', $text, $match);
var_dump($match);
40%

I’m attempting to modify the regex to ignore everything between open and closed brackets. So for the string "":{},[test,test2]" just :,[test,test2] should be returned.,(src: How to let regex ignore everything between brackets?),How to modify the regex such that data contained between [ and ] is not applied by the regex.,If you want to remove the {, }, , and " not inside square brackets, you can use

s = "": {}, "
print(s)
print(re.sub(r '"|{|}', "", s))
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