How sorted python dictionary while value is list?

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5 Answers

valuepythonsorteddictionary
90%

The dict class has items() method that returns a view of list of tuples, each tuple having key and value of each pair in a dictionary,,Finally, we shall use the dict

Example_snippet/controller/utility/_value.js/ markdict={"Tom":67, "Tina": 54. . .
markdict = {
   "Tom": 67,
   "Tina": 54,
   "Akbar": 87,
   "Kane": 43,
   "Divya": 73
}
marklist = list(markdict.items())
print(marklist)
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88%

sorted_x will be a list of tuples sorted by the second element in each tuple, dict(sorted_x) == x

Example_snippet/controller/utility/_value.js/ >>> x = {1: 2, 3: 4, 4: 3, 2: . . .
>>> x = {
      1: 2,
      3: 4,
      4: 3,
      2: 1,
      0: 0
   } >>>
   {
      k: v
      for k,
      v in sorted(x.items(), key = lambda item: item[1])
   } {
      0: 0,
      2: 1,
      1: 2,
      4: 3,
      3: 4
   }
Step 2 continued with >>> dict(sorted(x.items(), key. . .
>>> dict(sorted(x.items(), key = lambda item: item[1])) {
   0: 0,
   2: 1,
   1: 2,
   4: 3,
   3: 4
}
Step 3 continued with import operator x = {1: 2, 3: . . .
import operator
x = {
   1: 2,
   3: 4,
   4: 3,
   2: 1,
   0: 0
}
sorted_x = sorted(x.items(), key = operator.itemgetter(1))
Step 4 continued with import operator x = {1: 2, 3: . . .
import operator
x = {
   1: 2,
   3: 4,
   4: 3,
   2: 1,
   0: 0
}
sorted_x = sorted(x.items(), key = operator.itemgetter(0))
Step 5 continued with x = {1: 2, 3: 4, 4: 3, 2: 1, 0. . .
x = {
   1: 2,
   3: 4,
   4: 3,
   2: 1,
   0: 0
}
sorted_x = sorted(x.items(), key = lambda kv: kv[1])
Step 6 continued with import collections sorted_dic. . .
import collections

sorted_dict = collections.OrderedDict(sorted_x)
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72%

Now you’re ready to start sorting dictionaries by value like a Python pro!,How to Sort a Dictionary by Value in Python,Let’s say that you have a dictionary and you want to sort it by key-value pairs, You can do this by using two functions together: items() and sorted()

Example_snippet/controller/utility/_value.js/ customers = ['Kaley Fernandez'. . .
customers = ['Kaley Fernandez', 'Darius Rowland', 'Isaac Borthwick', 'Alexandria Kidd']
sorted_customers = sorted(customers)
print(sorted_customers)
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65%

How to handle a dictionary,,Dictionary has O(1) search time complexity whereas List has O(n) time complexity

Example_snippet/controller/utility/_value.js/ Input: key_value[2] = '64' . . .
Input:
   key_value[2] = '64'
key_value[1] = '69'
key_value[4] = '23'
key_value[5] = '65'
key_value[6] = '34'
key_value[3] = '76'

Output:
   1 2 3 4 5 6
Step 2 continued with Task 1:- Keys are 1 2 3 4 5 6. . .
Task 1: -

   Keys are
1 2 3 4 5 6
Step 3 continued with Input: key_value[2] = '64' . . .
Input:
   key_value[2] = '64'
key_value[1] = '69'
key_value[4] = '23'
key_value[5] = '65'
key_value[6] = '34'
key_value[3] = '76'

Output:
   (1, 69)(2, 64)(3, 76)(4, 23)(5, 65)(6, 34)
Step 4 continued with Task 2:- Keys and Values sorte. . .
Task 2: -
   Keys and Values sorted in alphabetical order by the key(1, 2)(2, 56)(3, 323)(4, 24)(5, 12)(6, 18)
Step 5 continued with Input: key_value[2] = '64' . . .
Input:
   key_value[2] = '64'
key_value[1] = '69'
key_value[4] = '23'
key_value[5] = '65'
key_value[6] = '34'
key_value[3] = '76'

Output:
   (4, 23), (6, 34), (2, 64), (5, 65), (1, 69), (3, 76)
Step 6 continued with Task 3:- Keys and Values sorte. . .
Task 3: -
   Keys and Values sorted in alphabetical order by the value[(1, 2), (5, 12), (6, 18), (4, 24), (2, 56), (3, 323)]
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75%

We can call the items() function in the dictionary to sort it by keys and return a list of tuples:,It is very useful when you want to return a list of tuples that are ordered by value in descending order,,Usually, after sorting, we will get a sorted list of tuples

Example_snippet/controller/utility/_python.js/ Counter. . .
Counter
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