How do I pass compile-time only global variables to my code?

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10 Answers

variables
90%

I found solution. Webpack DefinePlugin is what I need.,Electrical Engineering, Stack Overflow help chat

I found solution. Webpack DefinePlugin is what I need.

// webpack.confg.js

const webpack = require('webpack');
//...

module.exports = (env, argv) => ({
   //...
   plugins: [
      //...
      new webpack.DefinePlugin({
         IS_DEV: argv.mode !== 'production'
      })
   ]
})
88%

When you want to pass a const_val or another dependent_static,When you want to pass a reference to an object,Call all_constants::initialize_constants(), which will call initialize() for all existing const_val constants in main().

Pretag
 Pretag team - issue, fix, solve, resolve
72%

In computer programming, a global variable is a variable with global scope, meaning that it is visible (hence accessible) throughout the program, unless shadowed. The set of all global variables is known as the global environment or global state. In compiled languages, global variables are generally static variables, whose extent (lifetime) is the entire runtime of the program, though in interpreted languages (including command-line interpreters), global variables are generally dynamically allocated when declared, since they are not known ahead of time. ,Interaction mechanisms with global variables are called global environment (see also global state) mechanisms. The global environment paradigm is contrasted with the local environment paradigm, where all variables are local with no shared memory (and therefore all interactions can be reconducted to message passing). ,However, some predefined variables, known as superglobals are always accessible. They are all arrays. A general purpose one is the $GLOBALS superglobal, which contains all the variables defined out of function scope. Changes to its elements change the original variables, and additions create new variables. The superglobals $_POST and $_GET are widely used in web programming.

#include <stdio.h>

// This is the file-scope variable (with internal linkage), visible only in
// this compilation unit.
static int shared = 3;

// This one has external linkage (not limited to this compilation unit).
extern int over_shared;

// Also internal linkage.
int over_shared_too = 2;

static void ChangeShared() {
  // Reference to the file-scope variable in a function.
  shared = 5;
}

static void LocalShadow() {
  // Local variable that will hide the global of the same name.
  int shared;

  // This will affect only the local variable and will have no effect on the
  // file-scope variable of the same name.
  shared = 1000;
}

static void ParamShadow(int shared) {
  // This will affect only the parameter and will have no effect on the file-
  // scope variable of the same name.
  shared = -shared;
}

int main() {
  // Reference to the file-scope variable.

  printf("%d\n", shared);

  ChangeShared();

  printf("%d\n", shared);

  LocalShadow();

  printf("%d\n", shared);

  ParamShadow(1);

  printf("%d\n", shared);

  return 0;
}
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65%

What are the rules for local and global variables in Python?,How do I share global variables across modules?,Eric is an IDE built on PyQt and the Scintilla editing component.

>>> x = 10 >>>
   def bar():
   ...print(x) >>>
   bar()
10
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75%

Terms and Conditions, Dummies Custom Solutions

Pretag
 Pretag team - issue, fix, solve, resolve
40%

In lesson 6.3 -- Local variables, we covered that local variables are variables defined inside a function (or function parameters). Local variables have block scope (are only visible within the block they are declared in), and have automatic duration (they are created at the point of definition and destroyed when the block is exited).,Global variables are created when the program starts, and destroyed when it ends. This is called static duration. Variables with static duration are sometimes called static variables.,By convention, many developers prefix global variable identifiers with “g” or “g_” to indicate that they are global.

The above example prints:

3
3
5
22%

Usually when two variable with same name are defined then the compiler produces a compile time error. But if the variables are defined in different scopes then the compiler allows it.,How to access a global variable when there is a local variable with same name?,What if there exists a local variable with the same name as that of global variable inside a function?

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60%

Static declarations are resolved in compile-time. ,Example #6 Static variables with recursive functions,Example #7 Declaring static variables

NULL
object(stdClass) #1 (0) {
}
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48%

Update the parsing pass to support global variables. The parsing stage should now succeed on all valid examples in stages 1-10.,No global variable is defined more than once.,Declaring a function and a global variable with the same name is an error:

$ gcc - m32 example.c
ld: warning: The i386 architecture is deprecated
for macOS(remove from the Xcode build setting: ARCHS)
ld: warning: ignoring file / Applications / Xcode.app / Contents / Developer / Platforms / MacOSX.platform / Developer / SDKs / MacOSX10 .14.sdk / usr / lib / libSystem.tbd, missing required architecture i386 in file / Applications / Xcode.app / Contents / Developer / Platforms / MacOSX.platform / Developer / SDKs / MacOSX10 .14.sdk / usr / lib / libSystem.tbd
ld: dynamic main executables must link with libSystem.dylib
for architecture i386
clang: error: linker command failed with exit code 1(use - v to see invocation)
ld: warning: The i386 architecture is deprecated
for macOS(remove from the Xcode build setting: ARCHS)
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23%

Editing global scripts You can edit global scripts that can be called from other hooks in your schema.,Creating global scripts You can add global scripts that can be called from any other hooks in your schema.,Deleting global scripts You can delete global scripts in your schema.

$info = $session - > GetProductInfo();
$productInfo = GetProductInfo();
sub GetProductInfo {
   return $session - > GetProductInfo();
}
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