How do I get the filename of an input file and display it again on button click without uploading it?

Asked
Active3 hr before
Viewed126 times

7 Answers

buttonclickinput
90%

Step 3: Clicking "Next" will only display what's in Step 2 but it's grayed-out and instead of a Next button, there is a "Submit" button. It's like a confirmation if I am sure to upload the file. When I click on "Submit", that's the only time the file gets uploaded. , Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers ,Goals: 1. To copy the filename of the file I want to upload and display it when I click on a button but NOT upload it. 2. To be able to upload it when the Submit button is clicked.,You can further manipulate value of the file input field to isolate filename only using regex etc.

Here is a quick snippet to, hopefully, get you going:

<body>

    <input type="file" name="upload" id="upload">
    <div id="filename"></div>    

<script type="text/javascript">

    $('#upload').on('change',function(){
       // output raw value of file input
       $('#filename').html($(this).val()); 

        // or, manipulate it further with regex etc.
        var filename = $(this).val();
        // .. do your magic

        $('#filename').html(filename);
    });

    </script>
 </body>
88%

Example 2: In this example we will display the filename with the extension through an alert, by using the change() method and the file will be selected by the HTML <input type=”file”>.  ,The task is to get the file input by selected filename without the path using jQuery. To select the file we will use HTML <input type=”file”>. After that we will get the file name by using the jQuery change() method. This method is used in the JQuery to get the file input by selected file name. And the HTML <input type=”file”> is used to specify the file select field and add a button to choose a file for upload to the form.Syntax:  ,Below examples illustrates the approach:Example 1: In this example we will display the file name with the extension by using the change() method and the file will be selected by the HTML <input type=”file”>.  ,HTML <input type=”file”>:  

$(selector).change(function)
<input type="file">
load more v
72%

The string is prefixed with C:\fakepath\, to prevent malicious software from guessing the user's file structure.,Regardless of the user's device or operating system, the file input provides a button that opens up a file picker dialog that allows the user to choose a file.,Properties that apply only to elements of type file,When the multiple Boolean attribute is specified, the file input allows the user to select more than one file.

<input type="file" id="docpicker" accept=".doc,.docx,application/msword,application/vnd.openxmlformats-officedocument.wordprocessingml.document">
load more v
65%

click on link and call onclick event of file upload,pass selected filename to fileupload control in iframe and immediately post form in iframe,Instead of just uploading each file individually, I wanted to let the user select all the files he needs and then upload them all at the same time.,file names will be displayed in other control just for display purpose..... when u want to upload actual file, u have to get it from file upload control only.

here goes, complete .aspx page..... u can copy all code and create a new .aspx form and test....

<%@ Page Language="VB" AutoEventWireup="false" CodeFile="Default3.aspx.vb" Inherits="Default3" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
        <title>Test - file upload trick</title>
    <script type="text/javascript">
    function CallUpload()    
    {
        if(document.getElementById("FileUpload1").value=='')
        {
            document.getElementById("FileUpload1").click();
        }
        else if(document.getElementById("FileUpload2").value=='')
        {
            document.getElementById("FileUpload2").click();        
        }
        else if(document.getElementById("FileUpload3").value=='')
        {
            document.getElementById("FileUpload3").click();        
        }        
     
        return false;
    }
    function AddToList(evt)
    {
         var myOption; 

            myOption = document.createElement("Option"); 
            myOption.text = evt;
            myOption.value = evt;
            document.getElementById("lstFiles").add(myOption);
    }
    </script>
</head>
<body>
    <form id="form1" runat="server">
    <div>
         <br />
    add upto 3 files<br />
    
    <asp:FileUpload ID="FileUpload1" runat="server" Width="514px" onchange="javascript:AddToList(this.value);" style="display:none;"/>
    <asp:LinkButton ID="q0" runat="server" Text="link1" OnClientClick="return CallUpload();"></asp:LinkButton>
    <br />
    
    <asp:FileUpload ID="FileUpload2" runat="server" Width="514px" 
        onchange="javascript:AddToList(this.value);" style="display:none;"/>
    <br />
    
    <asp:FileUpload ID="FileUpload3" runat="server" Width="514px" 
        onchange="javascript:AddToList(this.value);" style="display:none;"/>
    <br />
    <asp:ListBox ID="lstFiles" runat="server" Width="221px"></asp:ListBox>
         <br />
         <br />
         <asp:Button ID="Upload" runat="server" Text="Button" />
    <br />
    
    </div>
    </form>
</body>
</html>
load more v
75%

If from is not a valid upload file, then no action will occur, and move_uploaded_file() will return false. , If from is a valid upload file, but cannot be moved for some reason, no action will occur, and move_uploaded_file() will return false. Additionally, a warning will be issued. ,See Handling file uploads for a simple usage example, The filename of the uploaded file.

load more v
40%

An HTML5 input form element must be included in the webpage that renders in the client’s browser;,The server-side resource is passed the FormData which contains the file,The following HTML5 tags provide the required components to add a file selector and an upload button to any web page:,A component must exist on the server to handle the file upload and save the resource locally;

The following HTML5 tags provide the required components to add a file selector and an upload button to any web page:

<input id="fileupload" type="file" name="fileupload" />
<button id="upload-button" onclick="uploadFile()"> Upload </button>

The button kicks off a method named uploadFile(), which contains the JavaScript file upload logic.

<script>
async function uploadFile() {
    let formData = new FormData();           
    formData.append("file", fileupload.files[0]);
    await fetch('/upload.php', {
      method: "POST", 
      body: formData
    });    
    alert('The file has been uploaded successfully.');
}
</script>
load more v
22%

A view handling this form will receive the file data in request.FILES, which is a dictionary containing a key for each FileField (or ImageField, or other FileField subclass) in the form. So the data from the above form would be accessible as request.FILES['file'].,Consider a form containing a FileField:,Notice that we have to pass request.FILES into the form’s constructor; this is how file data gets bound into a form.,Before you save uploaded files, the data needs to be stored somewhere.

from django
import forms

class UploadFileForm(forms.Form):
   title = forms.CharField(max_length = 50)
file = forms.FileField()
load more v

Other "button-click" queries related to "How do I get the filename of an input file and display it again on button click without uploading it?"